Chemistry, 14.06.2020 12:57 livie225

How many grams of Br2 are needed to form 67.1 g of AlBr3 ?

2Al(s)+3Br2(l)⟶2AlBr3(s)

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Answer from: Jasten

Approximately $60.3\; \rm g$ .

Explanation:

Look up the relative atomic mass of $\rm Al$ and $\rm Br$ on a modern periodic table:

$\rm Al$ : 26.982

. $\rm Br$ : 79.904

Calculate the formula mass of $\rm AlBr_3$ and $\rm Br_2$ :

$\begin{aligned}& M(\mathrm{AlBr_3}) = 26.982 + 3 \times 79.904 \approx 266.694\; \rm g \cdot mol^{-1} \\ & M(\mathrm{Br_2}) = 2\times 79.904 \approx 159.808\; \rm g \cdot mol^{-1}\end{aligned}$ .

Calculate the number of moles of formula units in $67.1\; \rm g$ of $\rm AlBr_3$ :

$\begin{aligned}n(\mathrm{AlBr_3}) &= \frac{m(\mathrm{AlBr_3})}{M(\mathrm{AlBr_3})} \\ &\approx \frac{67.1\; \rm g}{266.694\; \rm g \cdot mol^{-1}} \approx 0.2516\; \rm mol \end{aligned}$ .

Refer to the balanced equation for this reaction. The ratio between the coefficients of $\rm Br_2$ and $\rm AlBr_3$ in that equation is three-to-two. That corresponds to the ratio:

$\begin{aligned}\frac{n(\text{$\mathrm{Br_2}$, consumed})}{n(\text{$\mathrm{AlBr_3}$, produced})} &= \frac{3}{2}\end{aligned}$ .

It is already calculated that approximately $0.2516\; \rm mol$ of $\rm AlBr_3$ was produced through this reaction. Apply this ratio to approximate the (minimum) number of moles of $\rm Br_2$ that is consumed:

$\displaystyle \frac{3}{2} \times 0.2516\; \rm mol \approx 0.3774\; \rm mol$ .

Calculate the mass of that $0.3774\; \rm mol$ of $\rm Br_2$ :

$\begin{aligned}m(\mathrm{Br_2}) &= n(\mathrm{Br_2})\cdot M(\mathrm{Br_2}) \\ &\approx 0.3774\; \rm mol \times 159.808\; \rm g \cdot mol^{-1} \approx 60.3\; \rm g\end{aligned}$ .

Answer from: Quest

What do you mean by that? like the contents? the thc level?

Answer from: Quest

The answer to your question really depends on three things: how much water you have, how cold it is to start out, and how cold the things around it are. water actually freezes when it gets to 32 degrees fahrenheit (0 degrees celsius), but the time it takes to get there may be different. let's start with the first. if you take two glasses, and fill one with a tiny bit of water, and the other about halfway, then put them both in the freezer, the one with less water will freeze first (you can try this at home, but i recommend using plastic cups and not glass ones). now let's move on to the second part. let's say you have two glasses, and you fill one with really cold water that has been in the refrigerator, and the other with really hot water from the sink. if you put both of them in the freezer, the one that started out colder will freeze first. for the third part, let's imagine that you have two glasses with the same amount of water in them, and the water is at the same temperature. imagine putting one outside on a really really cold day in georgia, and having a friend in alaska put one outside on the same day. since it would be so much colder in alaska, the glass of water there would freeze before yours. so, if you took a tiny bit of really cold water in a glass, and put it outside on a cold day in alaska, it would freeze a lot faster than a big glass of hot water outside on a cold day in georgia.

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How many grams of Br2 are needed to form 67.1 g of AlBr3 ?

2Al(s)+3Br2(l)⟶2AlBr3(s)...

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