What volume (mL) of 7.48x10 -2 M phosphoric acid can be completely reacted with 115 mL of .244 M sodium hydroxide? Hint: balance equation

125ml - volume of phosphoic acid

Explanation:

The equation of the reaction is

H3PO4 + 3 NaOH ---> Na3PO4 + 3H2O

Such that I mole of H3PO4 reacts with 3 moles of  NaOH to produce the products above.

Given that

M1= Molarity of phosphoric acid = 7.48x10^-2 M

n1= number of moles of phosphoric acid = 1

V1=? ml

M2= Molarity  of Sodium hydroxide =0.244 M

V2= volume of sodium hydroxide= 115ml

n2=number of moles of sodium hydroxide = 3

Using the Dilution equation formulae,

M1V1/n1 = M2V2/n2

7.48X10-2 x V1 /1= 0.244M x 115ml/3

V1=0.244Mx115mlx1/0.0748M X 3

V1= 28.06/0.2244= 125.04ml

V1=125.04ml rounded up to 125ml