Assuming that the proximal histidine has a pKapKa of 6.00,6.00, you can use the Henderson–Hasselbalch equation to determine that the ratio of deprotonated to protonated histidines would be approximately 25:125:1 at a biological pHpH of 7.40.7.40. pH=pKa+log([A−][HA]) pH=pKa+log([A−][HA]) What would the ratio of deprotonated to protonated histidines be if the pHpH decreased to 6.40?
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Assuming that the proximal histidine has a pKapKa of 6.00,6.00, you can use the Henderson–Hasselbalc...
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