Text, 13.8."A natural gas mixture having a molal analysis of 60% CH4, 30% C2H6, 10% N2 is supplied to a furnace, where it burns completely with 20% excess air. Determine (a) the balanced reaction equation. (b) the air-fuel ratio, both on a molal and mass basis." DISCUSSION: How are the products of combustion with 20% excess air different from those that would be obtained with 100% theoretical (0% excess) air

we need the questions , i may then you.

i think its 100

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(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied