What mass of copper is required to completely replace silver from 4.00g of silver nitrate dissolved in water by the reaction cu(s) + 2 agno3 → cu(no3)2 + 2 ag.

Mass of copper is required to completely replace silver = 0,7493 grams

Stokiometry in Chemistry learns about chemical reactions mainly emphasizing quantitative, such as calculation of volume, mass, number, which is related to the number of ions, molecules, elements, etc.

In stoichiometry therein includes

•1. a relative atomic mass is a measurement of the mass of an atom relative to the mass of 1 carbon-12 atom

•2. The relative molecular mass is the sum of the mass of the entire atomic mass making up the molecule or is the sum of the relative atomic masses that make up the molecule

•3. Mol is a unit of the number of particles where 1 mole is the number of particles contained in a substance which is equal to many atoms in 12 gr C-12

1 mol = 6.0210²³ particles

V = n × Vm

V = volume of gas, liter

n = mole

Vm = molar volume (liters / mol)

Molar volume depends on conditions:

Conditions at T 0 ° C and P 1 atm

VM is 22.4 liters/mol.

Conditions at T 25 ° C and P 1 atm Vm in this condition = 24.4 liters / mol

While the number of moles can also be obtained by dividing the mass (in grams) by the relative mass of the element (Ar) or the relative molecular mass (Mr)

mole = gram / (Ar / Mr)

Reaction that happened

Cu(s) + 2 AgNO₃ → Cu(NO₃)₂ + 2Ag.

known 4 grams of silver nitrate AgNO ₃

From the reaction, equation shows the reaction coefficients of Cu and AgNO₃ = 1: 2 so that the mole ratio of both is also 1: 2

We specify the mole of AgNO₃

relative molecular mass AgNO₃ = 170

so mole AgNO3 = 4/170

= 0.0235

so that

mass = 0.0235./2 . relative atom mass

= 0,0118 . 63.5

= 0,7493 grams

convert 15.0 g Al to AlBr3

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methane gas (CH₄) is combusted

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the mass of 3.4 moles of nitric acid (HNO₃)

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the mass of excess reagent

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Keywords: Stokiometry, mole, grams, AgNO₃

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm

wher is the rest of the question