A 315-mL bag of potato chips is packaged at sea level (1.00 atm) where the temperature is 25oC. If this bag of chips is transported to Denver (where the pressure is 0.775 atm and the temperature is 18oC), what will the new volume of the bag be?

THE NEW VOLUME AT A PRESSURE OF 0.775 atm AND TEMPERATURE OF 18 °C IS 0.397 L

Explanation:

Using the combined gas equation

P1V1/T1 = P2V2/ T2

P1 = 1 atm

VI = 315 mL = 315 / 1000 L = 0.315 L

T1 = 25°C  25 + 273 K = 298 K

P2 = 0.775 atm

T2 = 18 °C = 18 + 273 K = 291 K

V2 = Unknown

Substituting the values into the equation, we obtain:

V2 = P1V1 T2/ P2 T1

V2 = 1 * 0.315 * 291 / 0.775 * 298

V2 = 91.665 / 230.95

V2 = 0.3969 L

The new volume at the given change in conditions is 0.397 L

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