The decomposition of hydrogen peroxide, H2O2, has been used to provide thrust in the control jets of various space vehicles. Determine how much heat (in kJ) is produced by the decomposition of 1.71 mol of H2O2 under standard conditions.

Explanation:

Hello,

In this case, the decomposition of hydrogen peroxide is given by:

Which occurs in gaseous phase, therefore the enthalpy of reaction is:

Oxygen is not included as it is a pure element. The enthalpies of formation for both hydrogen peroxide and water are -136.11 and -241.83 kJ/mol respectively, so we compute the enthalpy of reaction:

Then, the total heat that is released for 1.71 mol of hydrogen peroxide is:

Whose sign means a released heat.

Regards.

the electron configuration that you gave me has 16 electrons ergo it has 16 protons ergo it is the element sulfur.