You’re trying to remove dissolved iron from a solution. The theoretical yield for a reaction between sodium sulfide and iron(III) bromide is 0.721 kilogram of solid iron(II) sulfide. When you carried out the reaction, you got 530.0 grams. What is the percent yield? FREEBE HAVENT SEEN THIS QUESTION YET

ANSWER!!!
The percent yield of the reaction is 73.5%

73.5%

Explanation:

Step 1:

Data obtained from the question.

Theoretical yield = 0.721Kg

Actual yield = 530g

Percentage yield =..?

Step 2:

Conversion of 0.721Kg to grams. This is illustrated below:

1Kg = 1000g

Therefore, 0.721Kg = 0.721 x 1000 = 721g

Step 3:

Determination of the percentage yield.

The percentage yield can be obtained by using the following formula:

Percentage yield = Actual yield /Theoretical yield x 100

Percentage yield = 530/721 x 100

Percentage yield = 73.5%

Therefore, the percentage yield is 73.5%

oh it is true if thats what you are asking

b.

the accuracy of the data.