How many moles of KNO3 will be required to prepare 8.0L of 1.40 M KNO3?

11.2 moles of KNO3 will be required to prepare 8.0 L of 1.40 M KNO3

Explanation:

To answer this question, we need an understanding of the units of the term called molarity.

1.40M KNO3 means that there are 1.4 moles per dm^3 or per liter of the solution.

Now, since there are 1.4 moles in 1 liter

x moles will be present in 8.0 liters

Thus, mathematically;

x * 1 = 8 * 1.4

x = 11.2 moles

beta decay is the answer