What is the volume of a 4.0M solution that contains 374 grams of KNO3?'

0.93L

Explanation:

We'll begin by calculating the number of mole of present 374g of KNO3. This is illustrated below:

Mass of KNO3 = 374g

Molar mass of KNO3 = 39 + 14 + (16x3) = 101g/mol

Number of mole of KNO3 =..?

Mole = Mass /Molar Mass

Number of mole of KNO3 = 374/101 = 3.7 moles

Now, we can calculate the volume of the solution as follow:

Mole of KNO3 = 3.7 moles

Molarity = 4M

Volume =..?

Volume = mole /Molarity

Volume = 3.7/4

Volume = 0.93L

Therefore, the volume of the solution is 0.93L

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.