. Then:![Q = (25\,g)\cdot \left[\left(0.138\,\frac{J}{g\cdot ^{\circ}C} \right)\cdot (356.7^{\circ}C - 25^{\circ}C) + 296\,\frac{J}{g} \right]](/tpl/images/0678/4972/f4a24.png)
Calculate the amount of energy required to boil 25.00 g of mercury.
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