2KMnO4= K2MnO4+ MnO2+O2 how many grams of KMnO4 are required to produce 1.60 grams of O2

15.8 g of will be required to produce 1.60 grams of

Explanation:

To calculate the moles :

According to stoichiometry :

As 1 mole of is given by = 2 moles of

Thus 0.05 moles of is given by =  of

Mass of

Thus 15.8 g of will be required to produce 1.60 grams of

0

explanation:

488479

rvmoo+478)9.68

the millers tale is the answer.