If a car of 2 kg mass has a force of 8 Newtons exerted on it what is it’s acceleration a) 16 m/s^2
b) 4 m/s^2
c) 0.25 m/s^2

b) 4m/s^2

Explanation:

F=ma

F=8N

m=2kg

a=?

a=F÷m

8/2=4

acceleration=4m/s²

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm