What is the energy per mole of photons, in kJ/mol, emitted by an argon ion laser which produces a green beam with a frequency of 5.83x1014 Hz?

Energy per mole of photons = 2.31 × 10^2 KJ/mol

Explanation:

Energy, E = hf;

Where h is Planck's constant = 6.63 ×10^-34, and f is frequency of the photons.

E = 6.63 × 10^-34 × 5.8 × 10^14

E = 3.84 × 10^-22 KiloJoules

I mole of photons contains Avogadro's number of particles, 6.02 × 10^23

Therefore, the energy per mile of photon is 3.84 × 10^-22 KJ × 6.02 × 10^23

Energy per mile of photon = 2.31 × 10^2 KJ/mol

1 a

2 d

3 a

4 c

explanation:

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :