Chemistry, 04.06.2020 13:25 samone26

1 point A container with nitrogen, oxygen, and hydrogen has a pressure of 10.46
atm. If the pressure of nitrogen is 321 kPa and the pressure of oxygen is
74.0 psi, what is the pressure of hydrogen? *
2.25 atm
18.7 atm
4.90 atm
237 atm

Answers: 3

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Answers

Answer from: destineedeal1

2.25 atm

Explanation:

Given data

Pressure of N₂: 321 kPaPressure of O₂: 74.0 psiPressure of H₂: ?Total pressure: 10.46 atm

Step 1: Convert the pressure of nitrogen to atm

We will use the relationship 1 atm = 101.325 kPa.

$321kPa \times \frac{1atm}{101.325kPa} = 3.17 atm$

Step 2: Convert the pressure of oxygen to atm

We will use the relationship 1 atm = 14.6959 psi.

$74.0psi \times \frac{1atm}{14.6959psi} =5.04atm$

Step 3: Calculate the partial pressure of hydrogen

The total pressure is the sum of the partial pressures.

P = pN₂ + pO₂ + pH₂

pH₂ = P - pN₂ - pO₂

pH₂ = 10.46 atm - 3.17 atm - 5.04 atm

pH₂ = 2.25 atm

Answer from: destinyharris2586

P_H=2.25atm

Explanation:

Hello,

IN this case, we can apply the Dalton's law in order to understand the pressure behavior of a mixture as the summation of all the pressures of the compounds in the mixture, in this case, nitrogen, oxygen and hydrogen:

P_T=P_O+P_N+P_H

So, since we are asked to compute the pressure of hydrogen, we simply solve for it:

$P_H=P_T-P_O-P_N=10.46atm-74.0psi*\frac{1atm}{14.6959psi} -321kPa*\frac{1atm}{101.325kPa} \\\\P_H=2.25atm$

Best regards.

Answer from: Quest

14,16 18 reacts with group

Answer from: Quest

assuming that your periodic table has eighteen columns, you should highlight the four elements in the third column from the left of the table.

explanation

neutral atoms of elements after calcium contain d electrons. the energy of d orbitals of a particular main shell lies between the energy of the s and p orbitals of the next main shell. for example, electrons in the $3d$ have energy higher than those in the $4 s$ orbital while lower than those of the $4 p$ orbital.

by the aufbau principle, electrons fill orbitals one at a time, starting from those of the lowest energy. the $4s$ orbital is therefore filled right after $3p$ orbitals and before $3 d$ orbitals.

potassium has electron configuration $[\text{ar}] 4 s^{1}$ and calcium $[\text{ar}] 4 s^{2}$ . the s orbital of a main shell holds a maximum of two electrons. the next element would thus have the electron configuration $[\text{ar}] 4 s^{2} \; 3d^{1}$ and satisfy the requirements.

a neutral atom of the element contains three electrons on top of the most recent noble gas element. it should thus be placed in the third column of the periodic table. both scandium and yttrium would satisfy the conditions. an aufbau diagram indicates that the 4f orbital is filled before the 5d. however, it appears that exceptions exists for both lanthanum and actinium. neutral atoms of the two d-block elements also demonstrate the $ns^{2} \; (n-1) p^{1}$ and should be highlighted as well.

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1 point A container with nitrogen, oxygen, and hydrogen has a pressure of 10.46
atm. If the p...