What volume of product is produced when 20.0 Mg of liquid hydrogen reacts with
excess liquid oxygen in a rocket propellant reaction? The gas is formed at 101.325 kPa and 40.0 o C

The volume of product formed is 0.26 L

Explanation:

As is the the excess reagent, is the limiting reagent as it limits the formation of product.

According to stoichiometry :

2 moles of give = 2 moles of

Thus 0.01 moles of will give =  of

According to ideal gas equation:

P = pressure of gas = 101.325 kPa = 1 atm

V = Volume of gas = ?

n = number of moles = 0.01

R = gas constant =

T =temperature =

Thus the volume of product formed is 0.26 L

a

it is b that is the answer.