What volume of product is produced when 20.0 Mg of liquid hydrogen reacts with
excess liquid oxygen in a rocket propellant reaction? The gas is formed at 101.325 kPa and 40.0 o C

The volume of product formed is 0.26 L

Explanation:

As is the the excess reagent, is the limiting reagent as it limits the formation of product.

According to stoichiometry :

2 moles of give = 2 moles of

Thus 0.01 moles of will give =  of

According to ideal gas equation:

P = pressure of gas = 101.325 kPa = 1 atm

V = Volume of gas = ?

n = number of moles = 0.01

R = gas constant =

T =temperature =

Thus the volume of product formed is 0.26 L

8 m/s because for him to get the same amount of energy as ray is putting out, bobby, who weighs half as much as ray, needs to run twice as fast.

the answer is b. dilution