6) Find the pH of the following solutions:

a) 0.00010 M HClO4

b) 2.35 x 10-3 M HI

c) 4.678 x 10-5 M HNO3

d) 0.0000877 M HCl

e) 0.00020 M HF

f) 0.0000061 M H3O+

g) 4.3 x 10-3 M NaOH (This is a base! Remember you will be finding pOH first!)

h) 6.7 x 10-9 M KOH (This is a base! Remember you will be finding pOH first!)

i) 0.00044 M HCl

j) C

pH is the negative logarithm of hydrogen (oxonium) ion concentration of aqueous solutions.

Explanation:

Recall that pH is defined as the negative logarithm of hydrogen ion concentration. We are going to apply that definition here.

a) 0.00010 M HClO4

pH= -log[0.00010]

pH= 4

b) 2.35 x 10-3 M HI

pH= -log[2.35 x 10-3 ]

pH= 2.63

c) 4.678 x 10-5 M HNO3

pH= -log[4.678 x 10-5]

pH= 4.3

d) 0.0000877 M HCl

pH=-log[0.0000877]

pH= 4.1

e) 0.00020 M HF

pH= -log[0.00020]

pH= 3.7

f) 0.0000061 M H3O+

pH= -log[0.0000061]

pH= 5.2

g) 4.3 x 10-3 M NaOH

pOH= -log[OH^-]

pOH= -log[ 4.3 x 10-3 ]

pOH= 2.4

But

pH + pOH =14

Therefore

pH= 14-pOH

pH= 14 -2.4

pH= 11.6

h) 6.7×10^-9 M KOH

pOH= -log[OH^-]

pOH= -log[ 6.7 x 10-9 ]

pOH= 8.2

But

pH + pOH =14

Therefore

pH= 14-pOH

pH= 14 -8.2

pH=5.8

I) 0.00044M HCl

pH= -log[0.00044]

pH= 3.4

the earth would become to overheated and everything alive on it will eventually die from overheating. plants will eventually die as well, water will evaporate, and it will be nothing but a hot planet without anything living on it.