How much heat, in kJ, is required to raise the temperature of 50 g of water by 5.53°C? (Round to the nearest 10 kJ, and enter only numbers in your answer.) The specific heat capacity of water is 4.186 J/g·°C.

Explanation:

Hello,

in this case, the required heat to increase the water by 5.53 °C is computed by using the mass, heat capacity and change in temperature during the process:

Thus, for the given data we compute it in kJ:

Best regards.

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%

3 1/4 %

explanation: