1) Find the concentration of a solution containing 300g of NaCl and 2L of water.
a) First find the molar mass of NaCl using a periodic table.
b) Convert 300g of NaCl into Mols of NaCl
c) Divide the Mols of solute by 2L, the liters of solution.

a) 58.44 g/mol

b) 5.133 moles of NaCl

c) 2.566 M

Explanation:

a) The molar mass of NaCl is

   Na: 22.99

   Cl: 35.45

 NaCl= 58.44 g/mol

b) 300 grs of NaCl x (1 mol NaCl / 58.44 grs NaCl) = 5.133 moles of NaCl

c) M= n/L

   M = 5.133 moles NaCl/ 2L = 2.566 M NaCl

chemical digestion occurs in the stomach were hcl and pepsin forms chyme, the mouth in which salivary amylase breaks down starch to form bolus, and the small intestine specifically the duodenum.