A 0.125L solution of NaOH is neutralized by 0.0425L of a 0.65 M H2SO4 solution. What is the concentration of the NaOH solution?

0.442 M

Explanation:

The equation of the reaction must first be written down before the problem can be correctly solved.

2NaOH(aq) + H2SO4(aq) > Na2SO4(aq) + 2H2O(l)

Given that;

Concentration of acid CA= 0.65 M

Concentration of base CB=

Volume of acid CA= 0.0425L

Volume of base CB= 0.125L

Number of moles of acid = 1

Number of moles of base = 2

From;

CAVA/CBVB= NA/NB

CAVANB= CBVBNA

CB= CAVANB/VBNA

Substituting values;

CB= 0.65 × 0.0425 × 2 / 0.125 × 1

CB= 0.442 M

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