75 cm3 of Chemical A are mixed with 75 cm3 of Chemical B in a coffee cup. A thermometer is used and it is found that the initial temperature of the solution is 22.5 degrees Celsius and at it's peak, the solution reaches a temperature of 48.3 degrees celsius. Determine the amount of heat released in Joules.

Heat released is 16192J

Explanation:

The coffee cup calorimeter formula to determine the heat in a chemical process is:

q = m×c×ΔT

Where Q is heat involved in the reaction, m is mass of solution (150g assuming a density of 1 for both chemicals), C is heat capacity of the solution (4.184J/g°C assuming is the same heat capacity of water) and ΔT is change in temperature (48.3°C-22.5°C = 25.8°C)

Replacing:

q = 150g×4.184J/g°C×25.8°C

q = 16192 J

Thus, heat released is 16192J

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o