When 481 J of energy is added to 18.3 g of aluminum at 17.4°C, the temperature increases

to 46.6°C. What is the specific heat of aluminum?

THE SPECIFIC HEAT OF ALUMINIUM IS 0.900 Jg^-1K^-1

Explanation:

To solve this question, follow the following steps listed below:

1. Write the formulae for heat change in a reaction

Heat = m c ΔT

2. Write out their values and convert to standard units.

m = mass of aluminum = 18.3g

Heat = 481 J

T2 = final temperature = 46.6°C = 273 + 46.6 = 319.6 K

T1 = initial temperature = 17.4 °C = 17.4 + 273 K = 290.4K

C = specific heat capacity of aluminum = ?

3. Solve for the specific heat of aluminium

c = Heat / m ΔT

c = 481 J / 18.3 g * ( 319.6 - 290.4) K

c = 481 / 18.3 * 29.2

c = 481 / 534.36

c = 0.900 Jg^-1K^-1

In conclusion, the specific heat capacity of aluminum is 0.900 Jg^-1K^-1.

idk i’m struggling too

answer: e.   sour taste

explanation: acids are those substances which dissociates in water to give ions. as they dissociate to give ions, they act as electrolytes and thus are electrically conductive. acids are sour in taste. example: hcl

bases are those substances which dissociates in water to give ions or accepts ions. as they dissociate to give ions, they act as electrolytes and thus are electrically conductive. bases are bitter in taste. bases are slippery in nature.