If you want to make more shells (CaCO3) then which direction should the reaction proceed?

The reaction will proceed in the reverse direction

Explanation:

Now consider the equation;

CaCO3(s) ⇄CO2(g) + CaO(s)

This is a reversible reaction. The reaction could proceed in either the forward or the reverse reaction depending on the conditions of the reaction. Under certain conditions, the forward reaction is favoured, under certain conditions, the reverse reaction is favoured.

The direction in which the reaction proceeds depends on the desired products as the equilibrium position could be manipulated at will by altering the reaction conditions. If the desire is to produce more CaCO3, then the equilibrium position is manipulated so that it shifts towards the left hand side. This implies that the reverse reaction is favoured.

first, consult an activity series chart to determine if al is more reactive than fe. it is, so it will replace the fe. now, one can continue with the problem.

next, make sure you have a correctly balanced equation.

3feo + 2al ==> 3fe + al2o3

now, determine which reactant (feo or al) is in limiting supply.

moles feo present = 125 g x 1 mole/71.8 g = 1.74 moles

moles al present = 25.0 g x 1 mole/26.98 g = 0.927 moles

since from the balanced equation, it take 3 mol feo for every 2 mol al, al will be limiting.

you can determine this simply by dividing moles of each by their coefficient in the balanced equation. for example: 1.74/3 = 0.58 and 0.927/2 = 0.464. al is less, so it is limiting.

finally, using the stoichiometry in the balanced eq. determine mass of fe that can be produced from 0.927 moles of al.

0.927 moles al x 3 moles fe/2 moles al x 55.8 g/mole = 77.6 g

its first and third is your answer i did the qustion the fourth isnt right