Calculate the grams of CaCl2 necessary to make a 0.15M solution.

Gram molecular mass = 40 + (35.5)2 = 111g

Mass of in 1 mole = 111g

Mass of in 0.15 mole = 111 × 0.15 = 16.65 g

93.2 ml + 3920 ml = 4013 ml total  

(93.2 ml) * (2.03 m) / (4013 ml) = 0.0471 m

the volume in in l of the diluted solution would be 0.0471 m.

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