What volume would 3.00 moles of neon gas have at 295 K and 645 mmHg?

V = 85.619 L

Explanation:

To solve, we can use the ideal gas law equation, PV = nRT.

P = pressure (645 mmHg)

V = volume (?)

n = amount of substance (3.00 mol)

R = ideal gas constant (62.4 L mmHg/mole K)

T = temperature (295K)

Now we would plug in the appropriate numbers into the equation using the information given and solve for V.

(645)(V) = (3.00)(62.4)(295)

(V) = (3.00)(62.4)(295)/645

V = 85.619 L

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