1 point
For the reaction below, 100 g of each reactant available. Which reactant is
the limiting reactant? *
2MnO2 (s) + 4KOH (am) + O2(g) + Cl2(g) → 2KMnO4 (am) + 2KCI (cm) + 2 H20 (1)
[Molar Masses: MnO2 =86.9 8/mol; KOH=56.18/mol; O2 = 32.0 /mol; Cl2 = 70.9 %/mol]
кон
Mn02
02
CI2

tracks, burrows, eggshells, nests, tooth marks, or gastroliths

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2