TWO nitro (NO2) groups are chemically bonded to a patch of surface. They can't move to another location on the surface, but they can rotate
It turns out that the amount of rotational kinetic energy each NO2 group can have is required to be a multiple of £, where £= 1.0 x 10^24 J. In other words, each NO, group could have £ of rotational kinetic energy, or 2€, or 3€, and so forth - but it
cannot have just any old amount of rotational kinetic energy.
Suppose the total rotational kinetic energy in this system is initially known to be 38€. Then, some heat is removed from the system, and the total rotational kinetic energy falls to 6£. Calculate the change in entropy. Round your answer to 3 significant digits, and be sure it has the correct unit symbol.