A chemistry student mixes 25 milliliters of 3.0 M hydrochloric acid (HCl) with excess sodium hydroxide. The chemicals react according to this chemical equation:

HCl + NaOH → NaCl + H2O.

If the volume of the resulting solution is 68 milliliters, what is the concentration of sodium chloride?

1.1 mol/liter

Explanation:

You would use the M1V1 = M2V2 equation to solve this.

We know M1 is 3.0 M, V1 is 25 milliliters, and V2 is 68 milliliters. We need to find M2.

To find M2, first plug in what you know.

(3.0 M)(25 mL) = M2(68 mL)

Then, divide everything by 68 mL to get M2 by itself

Your answer should be a quite large decimal but I rounded it to 1.1 mol/liter.

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