F 15 g of C₂H₆ reacts with 60.0 g of O₂, how many moles of water (H₂O) will be produced? (Hint: use what you know about limiting reactant) *
10 points

1.5 mol H2O

Explanation:

2C2H6 + 7O2 -> 4CO2 + 6H2O

The limiting reactant is C2H6

30 g C2H6 ->1 mol C2H6

15 g C2H6   -> x                      x= 0.5 mol C2H6

2 mol C2H6 -> 6 mol H2O

0.5 mol c2H6 -> x                    x = 1.5 mol H2O

the grams   of   barium that   are in   2.3 x 10^23   atoms of barium   is   52.4 g (answer c)

    calculation

mass = moles   of ba   x molar   mass of ba

  molar mass of ba from periodic table=   137.3 g/mol

  use the   avogadro's law   constant   to   calculate the moles of barium

  that   is     1 mole =   6.02   x 10^23 atoms

                    ? moles = 2.3 x 10^23   atoms

by cross   multiplication

=(1 mole   x 2.3x 10^23 atoms)   / 6.02   x10^23 atoms)=   0.382   moles

mass   is therefore = 137.3   g/mol x 0.382 mol = 52.4 ( answer c)

explanation:

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