How many milliliters of a 0.8 M solution of citric acid would be needed to react with 15 grams of baking soda? Show your work.

75mL

Explanation:

Step 1:

The balanced equation for the reaction. This is illustrated below:

C6H8O7 + 3NaHCO3 → Na3C6H5O7 + 3CO2 + 3H2O

Step 2:

Conversion of 15g of baking soda (NaHCO3) to mole.

This is illustrated below:

Mass of NaHCO3 = 15g

Molar Mass of NaHCO3 = 23 + 1 + 12 + (16x3) = 23 + 1 + 12 + 48 = 84g/mol

Number of mole = Mass/Molar Mass

Number of mole of NaHCO3 = 15/84 = 0.179 mole

Step 3:

Determination of the number of mole of citric acid (C6H8O7) produced by the reaction. This is illustrated below:

From the balanced equation above,

1 mole of C6H8O7 reacted with 3 moles of NaHCO3.

Therefore, Xmol of C6H8O7 will react with 0.179 mole of NaHCO3 i.e

Xmol of C6H8O7 = 0.179/3

Xmol of C6H8O7 = 0.06 mole.

Step 4:

Determination of the volume of C6H8O7 needed for the reaction. This is illustrated below:

Molarity of C6H8O7 = 0.8 M

Mole of C6H8O7 = 0.06

Volume =..?

Molarity = mole /Volume

Volume = mole /Molarity

Volume = 0.06/0.8

Volume = 0.075L

Converting 0.075L to mL, we have:

1L = 1000mL

Therefore 0.075L = 0.075 x 1000 = 75mL.

Therefore, 75mL of citric acid (C6H8O7) is needed for the reaction.

the answers are

c and c

the term hydride is commonly named after binary compounds that hydrogen forms with other elements of the periodic table. hydride compounds in general form with almost any element, except a few noble gases. the trends and properties vary according to the type of intermolecular force that bonds the elements together, the temperature, its molecular masses, and other components. hydrides are classified into three major groups, depending on what elements the hydrogen bonds to. the three major groups are covalent, ionic, and metallic hydrides. formally, hydride is known as the negative ion of a hydrogen, h-, also called a hydride ion. because of this negative charge, hydrides have reducing, or basic properties. its special characteristics will be further discussed.

explanation: