The value of AH° for the reaction below is +128.1 kJ CH3OH (I)-CO (g) + 2H2 (g) How much heat is consumed when 87.1 g of hydrogen gas is formed? A) 2.76 x 103 kJ B) 5.52 x 103 kJ C) -5.52 x 103 kJ D) -2.76 x 103 kJ E) -128.1 kJ

A) 2.76 x 103 kJ

Explanation:

CH3OH (I)>CO (g) + 2H2 (g)

Number of moles contained in 87.1g of hydrogen gas= mass of hydrogen gas/ molar mass of hydrogen gas

Molar mass of hydrogen gas= 2gmol-1

Number of moles hydrogen gas = 87.1g/2gmol-1= 43.55 moles of hydrogen

1 mole of methanol yields 2 moles of hydrogen

x moles of methanol yields 43.55 moles of hydrogen

x= 43.55 moles of hydrogen × 1 mole of methanol/2 moles of hydrogen

x= 21.775 moles of methanol

Then;

If 1 mole of methanol absorbs 128KJ of energy

21.775 moles of methanol will absorb 21.775 × 128/1 = 2.7×10^3 KJ of heat

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in 1783 cavendish was working with his hydrogen gas and found that when he burned it and condensed the vapor it was water. this was very significant since it disproved the greek theory of elements completely since water was not a simple substance but the product of two gases. it was lavoisier who hearing of the experiment gave cavendish's gas the name hydrogen ("water-producer") and added that hydrogen burned by combining with oxygen and that water was a hydrogen-oxygen combination.

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