Consider the following generic chemical reaction:
2A+3B→3C How many moles of B are required to completely react with: 8 mol of A, 9 mol of A, 3 mol of A, and 10 mol of A?

The number of moles of B reacted in each case is obtained by stoichiometry.

The representation of a chemical process on paper is known as a chemical reaction equation. It must consist of a reactant side and a product side. The reactants combine to yield the product.

Given the reaction; 2A + 3B → 3C, we can see that the mole ratio of the reactants is 2 : 3. Hence;

2 moles of A reacts with 3 moles of B

8 moles of A reacts with  8 moles × 3 moles/2 moles

= 12 moles B

2 moles of A reacts with 3 moles of B

9 mol of A reacts with 9 mol × 3 moles/2 moles

= 13.5 moles of B

2 moles of A reacts with 3 moles of B

3 mol of A reacts with  3 mol × 3 moles/2 moles

= 4.5 moles of B

2 moles of A reacts with 3 moles of B

10 mol of A reacts with 10 mol × 3 moles/2 moles

= 15 moles of B

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The number of moles of B that will completely react with;

8 moles of A is 12 moles of B

9 moles of A is 13.5 moles of B

3 moles of A is 4.5 moles of B

10 moles of A is 15 moles of B

Explanation:

From the reaction, we have the mole ratio of the reactants is 2 moles of A combines with 3 moles of B to form 3 moles of C

Therefore, one mole of A which is 2 moles/2 will combine with 3/2 moles of B

Hence 8 moles of A will combine with 8×3/2 or 12 moles of B

9 moles of A will combine with 9×3/2 or 13.5 moles of B

3 moles of A will combine with 3×3/2 or 4.5 moles of B

10 moles of A will combine with 10×3/2 or 15 moles of B

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