A student does a titration with 14.80 mL of 0.225M H2SO4 and 25.00 mL of unknown LiOH solution. What is the molarity of the base Pls hurry

The molarity of the base is 0.2664 M

Explanation:

Firstly, we write the complete and balanced titration reaction.

 +        →     +  

From the reaction, we can identify that 1 mole of the acid reacted with 2 moles of the alkali (base) to yield salt and water only

We identify the following also from the question;

= 14.80 mL  , = 25.00 mL , = 0.225M and = ?

= 1 , = 2

We use the relation;

/ = /

Plugging the values, we have ;

(0.225 × 14.80)/1 = ( × 25.00)/2

= (2 × 0.225 × 14.80)/25

= 0.2664 M

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