How many grams of CuO would be required to produce 10.0 moles of
nitrogen gas in the following chemical reaction?
2 NH3(g) + 3 CuO(s) 3 Cu(s) + N2(g) + 3 H2O(g)

2390 CuO

Explanation:

                           2 NH3(g) + 3 CuO(s)  --->  3 Cu(s) + N2(g) + 3 H2O(g)

from reaction                         3 mol                               1 mol

given                                       x mol                               10.0 mol

x = 3*10.0/1 = 30.0 mol

M(CuO) = 63.5 + 16.0 = 79.5 g/mol

m(CuO) = 30.0 mol CuO * 79.5 gCuO/1 mol CuO = 2390 g CuO

atomic mass = 39

number of neutrons = 20

number of protons= 19

electronic configuration = 1s2 2s2 2p6 3s2 3p6 4s1

the number of electron in first shell = 2

number of electrons in n=3 shell = 8

metric time was an attempt to create a standard unit of time based off of 10, but it never took off an is not included in the metric system (si)