Iron has a mass of 7.87 g per cubic centimeter of volume, and the mass of an iron atom is 9.27 × 10-26 kg. if you simplify and treat each atom as a cube, (a) what is the average volume (in cubic meters) required for each iron atom and (b) what is the distance (in meters) between the centers of adjacent atoms?

a) is the average volume  required for each iron atom.

b) The distance between the centers of adjacent atoms is .

Explanation:

a) Mass of an iron = 7.84

Volume of iron =

Let the x atoms of iron weights 7.84 g and volume of .

Mass of an iron atom =

Volume of x atoms of iron =

Volume of an iron atom = v

is the average volume  required for each iron atom.

b) Volume of an iron atom = v

Volume of the cube =

Length of iron cube -= s

According to question we are treating iron atom as cube. So all the cubic iron atoms will have a same side.

The distance between the centers of adjacent atoms:

Horizontal distance of the center from the one face of the cubic iron atom:

=

Horizontal distance of the center from the one face of the another cubic iron atom:

=

The distance between the centers of adjacent atoms is .

im not exactly sure but i think its b!

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