Chemistry, 05.05.2020 10:54 tiffanyhmptn

Question 1
1 pts
What is the result when 12 grams of H2 and 28 grams of Nz react to
completion at STP.
3H2(g) + N2 --> 2 NH3
44 liters of NH3 are produced and 66 liters of H2 remain
22 liters of NH3 are produced and no liters of H2 remain
44 liters of NH3 are produced and no reactants remain
22 liters of NH3 are produced and 66 liters of N2 remain

Answers: 2

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Answer from: tina7659

Question:

a. 44 liters of NH3 are produced and 66 liters of H2 remain

b. 22 liters of NH3 are produced and no liters of H2 remain

c. 44 liters of NH3 are produced and no reactants remain

d. 22 liters of NH3 are produced and 66 liters of N2 remain

The most correct option is;

a. 44 liters of NH₃ are produced and 66 liters of H₂ remain

Explanation:

We are given the equation of the reaction as follows;

3H₂ (g) + N₂ (g) → 2NH₃

Therefore, 3 moles of H₂ reacts with 1 mole of N₂ to produce 2 moles of NH₃

Molar mass of H₂ = 2.01588 g/mol

Molar mass of N₂ = 28.0134 g/mol

Molar mass of NH₃ = 17.031 g/mol

Therefore

Number of moles of H₂ = $\frac{Mass \ of \ H_2}{Molar \ mass \ of \ H_2} = \frac{12}{2.01588 } = 5.953 \ moles$

∴ Number of moles of H₂ ≈ 6 moles

Number of moles of N₂ = $\frac{Mass \ of \ N_2}{Molar \ mass \ of \ N_2} = \frac{28}{28.0134 } = 0.9995 \ moles$

∴ Number of moles of N₂ ≈ 1 mole

Since 3 moles of H₂ reacts with 1 mole of N₂ to produce 2 moles of NH₃, we have an excess of approximately 3 moles of H₂ with 2 moles of NH₃ produced

From the universal gas equation we have;

$V = \frac{nRT}{P}$

Where:

For NH₃

n = Number of moles = 2

P = Pressure at STP = 1 atm

V = Volume = Required

T = Temperature at STP = 273.15 K

R = Universal Gas Constant =0.08205 L·atm/(mol·K)

Plugging the values, we have;

$V = \frac{2 \times 0.08205 \times 273.15}{1} = 44.8 \, L$

For the excess H₂

n = Number of moles = 3

P = Pressure at STP = 1 atm

V = Volume = Required

T = Temperature at STP = 273.15 K

R = Universal Gas Constant =0.08205 L·atm/(mol·K)

Plugging the values, we have;

$V = \frac{3 \times 0.08205 \times 273.15}{1} \approx 67 \, L$

Therefore, the most suitable option is 44 liters of NH₃ are produced and 66 liters of H₂ remain.

Answer from: Quest

For cyclohexane compounds drawn in a chair conformation: -axial bonds are vertical -equatorial bonds are parallel to two bonds within the ring. thus, as i assume the chair conformation is drawn: -the x group is in an axial position, as are the five other vertical bonds. -three axial bonds are on the top face of the ring -the other three axial bonds are on the bottom face the position of the second substituent on each ring carbon is equatorial. gauche groups must be on an adjacent carbon such as carbon 6 and carbon 2, and also gauche groups are rotated by 60 degrees relative to each other. drawing the newman projections for c1–c2 and c1–c6 aids in visualizing the groups that are gauche to the y group on c1. click this link and watch some academic videos that may you more understand the topic

Answer from: Quest

The state or quality of being humid.a quantity representing the amount of water vapor in the atmosphere or a gas.