Calculate the mass of the precipitate formed when 2.27 l of 0.0820 m ba(oh)2 are mixed with 3.06 l of 0.0664 m na2so4.

43.3 grams

Explanation:-

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

Thus

Thus

As 1 mole of reacts with 1 mole of

0.186 moles of reacts with =  of

Thus is the limiting reagent and will limit the formation of the products.

As 1 mole of gives with 1 mole of precipitate

0.186 moles of reacts with =  of precipitate

Mass of

Thus mass of the precipitate formed  is 43.3 grams.

b is the correct