Calculate the pressure of 2.78 g of Ne in a 5.00 L flask at -10°C

0.60 atm

Explanation:

Step 1.

Data obtained from the question.

This includes the following:

Mass of Ne = 2.78g

Volume (V) = 5L

Temperature (T) = –10°C

Pressure (P) =?

Step 2:

Determination of the number of mole of Ne.

The number of mole of Ne can be obtained as follow:

Mass of Ne = 2.78g

Molar Mass of Ne = 20g/mol

Number of mole Ne =?

Number of mole = Mass/Molar Mass

Number of mole of Ne = 2.78/20

Number of mole of Ne = 0.139 mol

Step 3:

Conversion of celsius temperature to Kelvin temperature. This can be achieved by as shown below:

Temperature (Kelvin) = temperature (celsius) + 273

Temperature (celsius) = –10°C

Temperature (Kelvin) = –10°C + 273

Temperature (Kelvin) = 263K

Step 4:

Determination of the pressure. The pressure can be obtained by using the ideal gas equation as follow:

PV = nRT

Volume (V) = 5L

Temperature (T) = 263K

Number of mole (n) of Ne = 0.139mol

Gas constant (R) = 0.082atm.L/Kmol

Pressure (P) =?

PV = nRT

P x 5 = 0.139 x 0.082 x 263

Divide both side by 5

P = (0.139 x 0.082 x 263) /5

P = 0.60 atm

Therefore the pressure is 0.60 atm

linda: 3 ; laura: 15

step-by-step explanation:

note that linda + laura's age is 18, and that linda is 12 years younger than her sister.

let "linda" = x , "laura" = y:

x + y = 18

x = y - 12

first, plug in y - 12 for x in the first equation:

(y - 12) + y = 18

simplify.

2y - 12 = 18

isolate the variable (y). note the equal sign, what you do to one side, you do to the other. do the opposite of pemdas. first add, then divide.

2y - 12 (+12) = 18 (+12)

2y = 18 + 12

2y = 30

(2y)/2 = (30)/2

y = 30/2

y = 15

next, plug in 15 for y in the second equation (the other equation would work too).

x = y - 12

x = (15) - 12

x = 3

linda's age is 3, laura's age is 15.

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i believe the answer is three water molecules