The combustion of propane (C3H8) in the presence of excess oxygen yields CO2 and H2O according to the equation:

C3H8 (g) + 5O2 (g) --> 3CO2 (g) + 4H2O

If 5 moles of propane and 5 moles of oxygen are present, which reactant is the limiting reactant?

What is the empirical formula of c6h18o3? ch3o c2h5o c2h6o c2h5o5

Problem page combustion of hydrocarbons such as pentane ( c5 h12 ) produces carbon dioxide, a "greenhouse gas." greenhouse gases in the earth's atmosphere can trap the sun's heat, raising the average temperature of the earth. for this reason there has been a great deal of international discussion about whether to regulate the production of carbon dioxide.(a) write a balanced chemical equation, including physical state symbols, for the combustion of liquid pentane into gaseous carbon dioxide and gaseous water. (b) suppose 0.350 kg of pentane are burned in air at a pressure of exactly 1 atm and a temperature of 20.0 degree c. calculate the volume of carbon dioxide gas that is produced.be sure your answer has the correct number of significant digits.

Calculate the mass of carbon in 97.0 g of sucrose c12h22o11