The final solution had a volume of 1.0L and a molarity of 0.925. How many moles of Nickel (II) chloride were present in the solution?

The moles of nickel (II) chloride were present in the solution are 0.925

Explanation:

Molarity is defined as the number of moles of solute dissolved per liter of the solution.

where,

Molarity = 0.925

n= moles of solute  = 0.2

= volume of solution in L = 1.0 L

Now put all the given values in the formula of molarity, we get

Therefore, the moles of nickel (II) chloride were present in the solution are 0.925

i'm pretty sure it is letter c.) car

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