You have the following equations:
2S (s) + 30 2 (g) - 250 3 (g), A H = -792 kJ
25 (s) + 20 2 (g) → 250 2 (g), A H = -
250 2 (g) + O 2 (g) — 250 3 (g), A H =
U
LL
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What is the missing AH?
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0 +198 kJ
0-198 kJ
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i
O
0-594 kJ
1
!
+792 kJ

Abeaker with 2.00×102 ml of an acetic acid buffer with a ph of 5.000 is sitting on a benchtop. the total molarity of acid and conjugate base in this buffer is 0.100 m. a student adds 4.70 ml of a 0.360 m hcl solution to the beaker. how much will the ph change? the pka of acetic acid is 4.740.

I'm learning about the periodic tables and what each subject's configuration is. for example, hydrogen is 1s^1, but i don't understand how you get that. can someone me understand how to figure out how to figure this out? sorry if the question makes no sense, but it would really a lot if you could me understand! you so much if you can!

What is a difference between a mixture of elements and a mixture of compounds