An aqueous solution is 65% (v/v) rubbing alcohol. How many millilitres of water are in a 95-ml sample of this solution?

The volume of water present in 95 ml of 65 % rubbing alcohol solution has been 33.25 ml.

The v/v has been the concentration representation of the volume of solute present in the total volume of the solution.

The given aqueous solution has 65 % v/v concentration of the rubbing alcohol. This states that there has been a presence of 65 ml of rubbing alcohol in 100 ml of the solution.

Since, in 100 ml sample there has been a presence of 65ml alcohol. The volume of water in 100 ml sample has been the remaining portion of the solution.

The aqueous solution of rubbing alcohol has been consisted of 35 ml water per 100 ml solution.

Since, 100 ml solution = 35 ml water

The volume of water present in 95 ml of 65 % rubbing alcohol solution has been 33.25 ml.

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The amount of water in a 95 mL sample of the solution is 33.25 mL

Explanation:

65% (v/v) rubbing alcohol is a solution containing 65 mL rubbing alcohol in 100 mL solution of the rubbing alcohol and water

Therefore, 95 mL sample of the solution will contain x mL of rubbing alcohol;

x = 65% × 95 =  0.65 × 95 = 61.75 mL rubbing alcohol and therefore, the amount of water contained = 95 - 61.75 = 33.25 mL

The amount of water in a 95 mL sample of the solution = 33.25 mL.

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