A → B is a first order reaction. Using the data below, what is the half-life in seconds? 0 sec, [A] = 1.22 M 3 sec, [A] = 0.86 M 6 sec, [A] = 0.61 M 9 sec, [A] = 0.43 M 12 sec, [A] = 0.31 M 15 sec, [A] = 0.22 M 18 sec, [A] = 0.15 M

Half-life time is 6s

Explanation:

A first order reaction follows the formula:

ln[A] = ln[A]₀ - kt

Thus, the graph of ln[A] vs t will have as slope -k.

Graphing the given values you will obtain the linear formula:

y = -0.1154x + 0.1994

R² = 0.9997

Thus, slope is -0.1154s⁻¹ and k is:

-k = -0.1154s⁻¹; k = 0.1154s⁻¹

Now, as half-life in a first order reaction is:

Half-life time is 6s

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.