Water was added to 175mL of a KOH solution until the volume was 250 mL and the molarity was 0.315 M. What was the molarity of the initial concentrated solution?

0.45 M

Explanation:

Now we need to make use of the dilution formula

C1V1= C2V2

C1= initial molarity of the solution which is the unknown

V1 = initial volume of the solution which is 175 ml

C2 =final molarity of the solution= 0.315 M

V2= final volume of solution= 250 ml

From C1V1= C2V2 we have;

C1= C2V2/V1

C1= 0.315 × 250/ 175

C1= 0.45 M

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.