How many moles of NaCl are present in a solution with a molarity of 8.59M 1 point

and 125 mL of solution? 1L = 1000 mL

Answer : The number of moles of NaCl present in a solution are, 1.07 moles.

Explanation : Given,

Molarity of = 8.59 M

Volume of solution = 125 mL  = 0.125 L      (1L = 1000 mL)

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

Now put all the given values in this formula, we get:

Therefore, the number of moles of NaCl present in a solution are, 1.07 moles.

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