2. Calculate the molarity of a solution in which 0.50 moles of MgCl2 are dissolved to produce 1.5 liters
of solution.

Molarity= 0.33M

Explanation:

From n= CV

n= 0.5mol, V= 1.5 ,C = ?

Substitute into above formula

0.5= C×1.5

C= 0.33M

when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.

i believe it is a.) released into

explanation: