How many moles of each ion are present in 2.55 L of solution containing 23.6 g of the solute in the ionic compound NaCl

0.404 moles Na⁺ and 0.404 moles Cl⁻

Explanation:

In the solution you have 23.6g of NaCl. As molar mass of NaCl is 58.44g/mol. Moles you have present are:

23.6g NaCl × (1mol / 58.44g) = 0.404 moles of NaCl

As you can see in the formula, each mole of NaCl contains 1 mole of Na⁺ and 1 mole of Cl⁻. Thus, moles of each ion are:

0.404 moles Na⁺ and 0.404 moles Cl⁻

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