In a container, there are 6.0 moles of gas with a volume of 120 liters at a temperature of 800.0 K. What is the pressure of the gas inside the container?

3.28 atm

Explanation:

n = 6.0 moles

Volume V = 120L

T = 800K

P = ?

R = 0.082 L.atm/ mol.K

From ideal gas equation,

PV = nRT

P = pressure

V = volume of the gas

n = number of moles

R = ideal gas constant

T = temperature of the gas

PV = nRT

P = nRT / V

P = (6 * 0.082 * 800) / 120

P = 393.6 / 120

P = 3.28 atm