2LiOH(s) + CO2(g) → Li2CO3(s) + H2O(l)

a. What mass of lithium hydroxide (LiOH) would be needed to react with 3.575 L of carbon dioxide gas?

7.613 kg

Explanation:

Since you need a ratio of 2 moles of LiOH for each mole of CO2, you can find the mass of LiOH that you need. The first thing that you need to do is to find the number of moles that 3.575 L of carbon dioxide gas is. At STP, there are 22.4 liters of gas in a mole, meaning that there are about 0.159 moles of carbon dioxide. Multiplying this by 2 you get 0.318 moles. The molar mass of LiOH can be calculated by adding together the molar masses of each of the constituents. Lithium has a molar mass of 6.941, oxygen has a molar mass of about 16, and hydrogen a molar mass of about 1. Adding this together you get a molar mass of 23.941kg, which for 0.318 moles is just 23.941*0.318=7.613 kg. Hope this helps, and PM me with questions!