What is the new pressure acting on a 2.5 l balloon if its original volume was 5.8 l at 3.7 ATM of pressure?

The new pressure is 8.58 atm

Explanation:

Using Boyle's law which states that the pressure of a gas is inversely proportional to the volume of the gas and mathematically written as;

         P1 V1 = P2 V2

P1 = 3.7atm

V1 = 5.8L

V2 = 2.5L

P2 = ?

Equate the values to the equation and solve for P2:

P2 = P1 V1 / V2

P2 = 3.7 * 5.8 / 2.5

P2 = 21.46 / 2.5

P2 = 8.584 atm

The new pressure acting on the balloon is therefore 8.58atm

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